Using typedef struct as a function parameter

[Phazon]

I have a couple of structs that I'm using, which work fine, but I want to pass one through as a parameter of a function and I'm not sure how to do it.

typedef struct
{
	std::string move;
	int moveScore;
} moveOption;

typedef struct
{
	std::string pMove;
	moveOption option[POSSIBLEMOVES];
} moveDecision;


std::string ChooseBestMove(std::string pMove, moveDecision decision); //error here 

Any help would be appreciated.

[Zhuge]

You don't need to use typedefs like that in C++, but otherwise the code looks fine. What's the error?

[Phazon]

I don't seem to be getting the error any more. I first got it when the structs were declared after the function, but I placed them before the function and still got the error (which was an undeclared identifier on the function). I must be confused. Sorry about that.

Out of curiosity though, why don't I need to pass typedefs as parameters?

[firedraco]

He means that in C++ you don't need to put the typedef there at all; it is done for you automatically.

Ex:

struct arg {
  int x,y;
};

//later
arg some_arg_instance;

[Phazon]

Ah right, I understand. Thanks.

[zb0S216C]

See here: http://www.cplusplus.com/forum/beginner/89419/#msg480308

_Wazzak