template specialisation
Hi,
Can anyone please tell me why the second function cannot be a specialization to the first ?? this code wouldnt run,
template <typename T> void f(T*) //1
template <> void f<int *>(int *) //2
but is fine if I include another template,
template <typename T> void f(T) //3
I am not able to understand why 2 can be specialization of 3 but not 1..
Can anyone please tell me why the second function cannot be a specialization to the first ?? this code wouldnt run,
template <typename T> void f(T*) //1
template <> void f<int *>(int *) //2
but is fine if I include another template,
template <typename T> void f(T) //3
I am not able to understand why 2 can be specialization of 3 but not 1..
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