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Use of "%" operator in this way.

Dec 30, 2012 at 1:50am
Xecutive (3)
I need a little help in understanding this, if someone could.

1
2
 
if ((iii % 3)==0)
        continue;


I was told that if iii was divisible by 3 the if statement would return true.

I don't understand what the % dose in the equation.

Last edited on Dec 30, 2012 at 1:54am
Dec 30, 2012 at 2:03am
closed account (zb0S216C)
It's the modulus operator: its job is to divide the left operand by the right operand and then return the remainder. For example, 7 % 3 is 1 because 3 goes into 7 twice but the 1 is left over.

Wazzak
Last edited on Dec 30, 2012 at 2:04am
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