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problem in nested loop (C programming)

artdeep (8)
how can i make a code that(the output) appear like these(in nested looping section):

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Please enter an integer>5
     1     
    121
   12321
  1234321
 123454321


Disch (13742)
Have an outer loop which does each row.

In that loop have 2 more loops. One which counts up to the row number, and another which counts down from it. Each printing numbers as they go.
artdeep (8)
can you show me the code..just now i have programming class in my university..i sat on the back..so i didnt notice anything about this nested loop section..and plus im blurred..

so can you help me for this output..i mean..can you help me with the code..maybe with that i can learn it
Disch (13742)
can you show me the code


No. Not unless you show me you are making an effort to do it yourself. This isn't a "do my homework for me" site.
artdeep (8)
im sorry..ok...i have done a bit..

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#include <stdio.h>
#include <conio.h>

int main (void)

{
    int num, row, col, i;
    printf("Please enter a number:");
    scanf("%d", &num);
    
    for(row=0; row<num; row++){
               
            for(col=1; col<(num*2-1); col++){
                    printf(" ");
                    if (col==4)
                    printf("%d", num);
            }
    printf("\n");
    }
    
 
 
 
    
getch();
return 0;
}


in that code what is the problems..
Disch (13742)
Alright. =)
I don't mind helping people figure stuff out, but I don't like to hand out solutions, either. "Teach a man to fish", etc, etc.

You have the nested loop idea right, but it would probably help to split the job up into several parts. This is how I would approach the problem:

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for(row = 1; row <= num; ++row)
{
  // have a loop here which draws the appropriate number of spaces

  // have another loop here which prints 1 up to the current row number (row)

  // have a 3rd loop here which prints numbers counting down from 'row'

  printf("\n");
}
artdeep (8)
Thx!!..i will try this ....thank you very much..ill will inform u aftr i get the output...thx very much!
artdeep (8)
I GOT IT!!!thx2!!!!

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#include <conio.h>
#include <stdio.h>

int main ()
{
    int i , j ,num, k,l ;
    
    
    printf ("Enter an integer > ");
    scanf ("%d",&num);
    
    for (i=1; i<=num; i++)
        {
        
              for (k=num; k>i; k--)
                  {
                      printf (" ");
                      
                  }
              for (j=1; j<=i; j++)
                  {
                      printf ("%d",j);
                  }
              for (l=j-2; l!=0; l--)
                  {
                      printf ("%d",l);
                  }
                 
              printf("\n");
        }
    
    getch();
    return (0);
}



Last edited on
artdeep (8)
and one more..how can there'll be these kind of output??

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enter an integer >5
    1
   2 2
  3   3
 4     4
555555555


how can there'll be an empty spaces between the number..can you help me..
Last edited on
Disch (13742)
Congrats @ your solution. =)

This new problem is more or less the same idea. Take it one row at a time. Try to look at the desired output and construct a logic flow for yourself.

For this one... it might help to treat the top and bottom rows seperately from the inner rows:

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// print top row

for( ... )
{
  // print inner rows
}

// print bottom row


Notice that all the inner rows all follow a pattern. They all start with some spaces, print a number, have some more spaces, then print that number again. Figure out the pattern, then it should be easy to translate it into code.
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