Help creating class objects

Error codes. I always wondered if real programmers remember any of those. Anyway, you should post the full compilation errors.

That being said, main() must return an int.

int main(int argc, char** argv)
{
  // Code
  return 0;
}

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you have to first overload the operator [] for row. if you dont know how to do that then do vector<row> rrr(2). then you can treat it like a normal array

Thanks.

maeriden - I just edited my post.

Aramil of Elixia - I know how to overload the operator [] but what should be
in "the body"?
Anyway - I can't understand what do you mean when you say: "do vector<row> rrr(2)" <--- Where?
Please write the full main with the vector <> ..... thanks!

you have to first overload the operator []

No, 'rrr' is a standard array, not a Row object

maeriden - I think you're right.

I'm coming from C# world and it's so so so easy!

What's the problem creating an array of objects of class THAT I HAVE BEEN CREATED?!

;)

yes its a row object. he declared it with type row. so you have to overload the [] operator which i dont know how to do and @ blabla just #include <vector> then @ line 24 replace whats there with the vector code

This is what I get now:

"Error 1 error LNK2019: unresolved external symbol "public: __thiscall Row::Row(void)" (??0Row@@QAE@XZ) referenced in function "void __cdecl std::_Uninit_def_fill_n<class Row *,unsigned int,class Row,class std::allocator<class Row>,class Row>(class Row *,unsigned int,class Row const *,class std::allocator<class Row> &,class Row *,struct std::_Nonscalar_ptr_iterator_tag)" (??$_Uninit_def_fill_n@PAVRow@@IV1@V?$allocator@VRow@@@std@@V1@@std@@YAXPAVRow@@IPBV1@AAV?$allocator@VRow@@@0@0U_Nonscalar_ptr_iterator_tag@0@@Z) Desktop\test_project\test_project\testRow.obj test_project"

plus

LNK 1120

post your code

#include <iostream>
#include <vector>
using namespace std;
	
class Row 
{
public:
	
	int nLength;


	Row();
	 Row(int length)
	 {
		 this->nLength = length;
	 }

	
};
void main()
{
	Row a(2);
	Row b(2);

	vector<Row> rrr(2);
	
	rrr[0] = a;
	rrr[1] = b;

	cout << rrr[0].nLength << endl;

}

line 12 your constructor needs to have {} and not the ;. i could be wrong but i think you have to overload the = operator before doing lines 28 and 27 do instead do the data members

yes its a row object.

No, it's an array of 2 Row objects

Quoting a guy from stackoverflow about LNK2019

This error often means that some function has a declaration, but not a definition.

You have to define Row's default ctor, even if it doesn't do anything

now your getting nit picky. i wrote that because you said rrr is a standard array not a row object. and actually no. it is a row object that holds two rows. like int array[2] is an int array that holds 2 ints. its type is still int object

OMG it works!

#include <iostream>
using namespace std;
	
class Row 
{
public:
	
	int nLength;


	Row()
	{

	}
	 Row(int length)
	 {
		 this->nLength = length;
	 }

	
};
void main()
{
	Row a(2);
	Row b(2);

	Row* rrr = new Row[2];
	
	rrr[0] = a;
	rrr[1] = b;

	cout << rrr[0].nLength << endl;

}

The stupi****......

Thanks again.

ur welcome.... wait it let you do an array? thats wierd...

I suggest modifying main to make it like a standard main. I remember people having errors because of that

its type is still int object

Its type is int*

yup

MikeyBoy (5631)

like int array[2] is an int array that holds 2 ints. its type is still int object

No it isn't. It's type is an array of int objects. If you try and use array as if it were an int, you will run into all sorts of problems.

C++ is a typed language, and you need to be precise about types when talking about it.

In your example:

array[0] is an int object.
array[1] is an int object.

array is not an int object. If you treat it as an int object, then you will make mistakes.

You can call it "nit picky", but successful programming is about being nit picky.

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Hi MikeyBoy -

Can you extend about nicpicky?