Guessing number within 2 of the number

[destro]

I'm stuck on this program it has you generate a random number from 0 to 9 and then you have to output how close they where to the number. I can't get it to show that "Your guess was within 2 of the number" and then you have to show that "your guess is greater than 2 of the number". Any help would be great thanks here my code that i ahve so far.

#include<iostream>
using namespace std;
int main()
{
int num;
cout << "Try and choose a number from 0 to 9 by enterng it now " << endl;
cin >> num;
const int DIVISOR = 10;
const int NUM = 1;
int x;
int result;
srand((unsigned)time(NULL));
for(x = 0; x < NUM; ++x)
{
result = rand() % DIVISOR;
cout << result << " " << endl;
if(result == num)
cout << "You guessed correct" << endl;
else
if (result > num || result < num)
cout << "you were off by 2 " << endl;
else
cout << "You were off by more than 2" << endl;
}
system("pause");
return 0;
}

[eker676]

To test for within two of the number.

abs(result - number) <= 2

To for greater than two

abs(result - number) > 2

[destro]

where would that go in my code?

[awasteoflife]

you need:

if ((num >= result-2)  && (num <= result+2))
cout << "you were off by 2 " << endl;

BTW, here are some ways you could improve your program

#include <iostream>
using namespace std;
int main()
{
int num;
cout << "Try and choose a number from 0 to 9 by entering it now " << endl;
cin >> num;
//This bit makes sure the user chooses the correct number.
while(num > 9 || num < 0)
{
     cout << "Please choose a number between 0 and 9." << endl;
     cin >> num;
}
//
const int DIVISOR = 10;
const int NUM = 1;
int x;
int result;
srand((unsigned)time(NULL));
for(x = 0; x < NUM; ++x)
{
result = rand() % DIVISOR;
cout << result << " " << endl;
if(result == num)
     cout << "You guessed correct" << endl;
//
else if ((num >= result-2)  && (num <= result+2))
     cout << "You were within 2 " << endl;
//
else
     cout << "You were off by more than 2" << endl;
}
// It is bad practice to use system('pause')
//Instead use a loop that ends when the user types 'x'
while(TRUE)
{
     char exit;
     cin >> exit;
     if (exit = 'x')
          break;
}
//
return 0;
}

[destro]

Thank you so much i'll play around with the code a bit.

[eker676]

Instead of

if(result == num)
     cout << "You guessed correct" << endl;
//
else if ((num >= result-2)  && (num <= result+2))
     cout << "You were within 2 " << endl;
//
else
     cout << "You were off by more than 2" << endl;
}

Use what I recommended, it is much easier

#include <cmath>
if(result == num)
{
  cout << "You guessed correct!\n";
}
else if( abs(result - num) <= 2)
{
  cout << "You were within 2.\n";
}
else
{
  cout << "You were not within 2.\n";
}

Instead of system("pause");
Try this.

std::cout << "Press Enter to exit...";
std::cin.clear();  // brilliant!
std::cin.sync();   // brilliant!
std::cin.ignore( std::numeric_limits <std::streamsize> ::max(), '\n' );  // lets the user type anything up-to and including the Enter key  

btw: This code was taken from a post made by Duoas in the Console Closing Down Thread

Just add #include <limits>

[destro]

Thanks for all the great help. I needed it.