Pass by reference not working
Nov 10, 2012 at 8:47pm UTC
I don't understand why the function call (convertFtoC or convertCtoF) is not working. It seems like everything else is working but the function call is not accessing the function I created above.
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#include <iostream>
using namespace std;
void convertFtoC( double & f )
{
(f - 32) * 5.0/9.0;
}
void convertCtoF( double & c )
{
(c + 32) * 9.0/5.0;
}
int main()
{
char yorn;
while (! ( (yorn == 'n' ) || (yorn == 'N' ) ) )
{
char answer;
double fdeg, cdeg;
cout << "Please enter C if you want to enter a degree in Centigrade, F if you want to enter a degree in Fahrenheit." << endl;
cin >> answer;
if ( (answer == 'C' ) || (answer == 'c' ) )
{
cout << "Please enter a number to be converted to Fahrenheit" << endl;
cin >> cdeg;
cout << "You entered " << cdeg << " Centigrade, " ;
convertCtoF(cdeg);
cout << "which is " << cdeg << " Fahrenheit." << endl;
}
if ( (answer == 'F' ) || (answer == 'f' ) )
{
cout << "Please enter a number to be converted to Centigrade" << endl;
cin >> fdeg;
cout << "You entered " << fdeg << " Fahrenheit, " ;
convertFtoC(fdeg);
cout << "which is " << fdeg << " Centigrade" << endl;
}
cout << "Do you want to do another conversion?" << endl;
cin >> yorn;
}
return 0;
}
Nov 10, 2012 at 9:04pm UTC
You don't actually do anything to the variables on lines 6 and 11. Use '=' to set f and c to whatever you need them to be.
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f = (f - 32) * 5.0/9.0;
c = (c + 32) * 9.0/5.0;
Last edited on Nov 10, 2012 at 9:04pm UTC
Nov 11, 2012 at 12:23am UTC
thank you, something so simple
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