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Program not working

Showdon (40)
I'm trying to make a program that records orders taken then displays how many of which order was taken and the total for the orders. The program has to include a for loop. Any suggestions?

A restaurant has 3 lunch combos for customers to choose:
Combo A: Fried chicken with cold slaw [price: 6.00]
Combo B: Roast beef with mashed potato [price: 6.25]
Combo C: Fish and chips [price: 5.75]

Write a program to calculate how much a group of customers should pay. The program first asks how many customers there are in the group. Then it asks the combo ordered by each customer. If case a customer does not want to order anything, the cashier will enter X, which means order nothing, into the program. When every customer in the group has placed his/her order, the program will display the number of each combo ordered and the total amount of this group’s bill.
TEST CASE

INPUT EXPECTED OUTPUT
Number of customer in the group: 5
Combos ordered:
C B C X A Number of combo A ordered: 1
Number of combo B ordered: 1
Number of combo C ordered: 2
Total amount due: 23.75


My code:
// Lab0903.cpp -
// Created by Taft Sanders 10/12/12

#include <iostream>

using namespace std;

int main( )
{
int customer=0;

cout<<"Number of customers in the group: ";
cin>>customer;

for (int order; order<=customer; order++)
{
char combo=' ';
int a=0;
int b=0;
int c=0;

cout<< "What combo would you like: ";
cin>> combo;

if (combo=='A' || combo=='a')
{
a++;
}
else if (combo=='B' || combo=='b')
{
b++;
}
else if (combo=='C' || combo=='c')
{
c++;
}
else if (combo=='X' || combo=='x')
{
cout<< "Customer ordered nothing";
}
}
int a;
int b;
int c;
cout<<"Number of combo A ordered: "<< a << endl;
cout<<"Number of combo B ordered: "<< b << endl;
cout<<"Number of combo C ordered: "<< c << endl;

double comboA=6.00;
double comboB=6.25;
double comboC=5.75;
double total=0;

total=(comboA*a)+(comboB*b)+(comboC*c);

cout<<"Total amount due: "<< total<<endl;

system("pause");
return 0;
}
Lowest0ne (1536)
Please use code tags (the <> button), and perhaps some indentation too. It looks like you define a, b, and c in two places. Put the first declaration at the beginning of main(), and then remove the second.
Showdon (40)
I removed the 2nd declaration of the variables and moved them to the top of main. I still get basically the same output, just different numbers.

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// Lab0903.cpp - 
// Created by Taft Sanders 10/12/12

#include <iostream>

using namespace std;

int main( )
{
int customer=0;
int a;
int b;
int c;

cout<<"Number of customers in the group: ";
cin>>customer;

for (int order; order<=customer; order++)
{
    char combo=' ';
    int a=0;
    int b=0;
    int c=0;
    
    cout<< "What combo would you like: ";
    cin>> combo;
    
    if (combo=='A' || combo=='a')
    {
                   a++;
    }
    else if (combo=='B' || combo=='b')
    {
                   b++;
    }
    else if (combo=='C' || combo=='c')
    {
                   c++;
    }
    else if (combo=='X' || combo=='x')
    {
                   cout<< "Customer ordered nothing";
    }
}

cout<<"Number of combo A ordered: "<< a << endl;
cout<<"Number of combo B ordered: "<< b << endl;
cout<<"Number of combo C ordered: "<< c << endl;

double comboA=6.00;
double comboB=6.25;
double comboC=5.75;
double total=0;

total=(comboA*a)+(comboB*b)+(comboC*c);

cout<<"Total amount due: "<< total<<endl;

system("pause");
return 0;
}


Is there a way to post a screenshot of my results so that you may see what I get?
Showdon (40)
Figured out how post that screenshot. Here is what I'm getting.


Number of customers in the group: 5
Number of combo A ordered: 2686792
Number of combo B ordered: 2
Number of combo C ordered: 48
Total amount due: 1.6121e+007
Press any key to continue . . .
Showdon (40)
Well I'm still shooting in the dark but I think I might be getting somewhere. I took the 2nd declaration of the variables a,b,c out of the for loop. Now my program is completely skipping my for loop and going straight to the end. How do I get my for loop to compile with the program?

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// Lab0903.cpp - Display the number of combos order by type and total amount due
// based on the number of guests enetered.
// Created by Taft Sanders 10/12/12

#include <iostream>

using namespace std;

int main( )
{
int customer=0;
int a=0;
int b=0;
int c=0;

cout<<"Number of customers in the group: ";
cin>>customer;

for (int order; order<=customer; order++)
{
    char combo=' ';
    
    cout<< "What combo would you like: ";
    cin>> combo;
    
    if (combo=='A' || combo=='a')
    {
                   a++;
    }
    else if (combo=='B' || combo=='b')
    {
                   b++;
    }
    else if (combo=='C' || combo=='c')
    {
                   c++;
    }
    else if (combo=='X' || combo=='x')
    {
                   cout<< "Customer ordered nothing";
    }
}

cout<<"Number of combo A ordered: "<< a << endl;
cout<<"Number of combo B ordered: "<< b << endl;
cout<<"Number of combo C ordered: "<< c << endl;

double comboA=6.00;
double comboB=6.25;
double comboC=5.75;
double total=0;

total=(comboA*a)+(comboB*b)+(comboC*c);

cout<<"Total amount due: "<< total<<endl;

system("pause");
return 0;
}




Number of customers in the group: 100
Number of combo A ordered: 0
Number of combo B ordered: 0
Number of combo C ordered: 0
Total amount due: 0
Press any key to continue . . .
RememberToSmile (1)
Did you ever figure out what was wrong because, I would like to know too.. Thanks
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