I need something that can hold multiple integers.

[DJLad16]

I need some sort of variable that I can use to hold multiple integers and can print out basically. e.g

something userNumber = {a, b, c, d, e} // something along those lines. 
cout << "Please enter 5 Number: " << endl;
cin >> userNumbers;
cout << "Your chosen numbers" << userNumbers << endl; // prints out the 5 numbers the user has entered. 

[TheJJJunk]

You want an array.
http://www.cplusplus.com/doc/tutorial/arrays/

[DJLad16]

I was thinking about using an array, but I've never used them with integers before so I didn't know how to do it. But thanks for reminding me :D

[DJLad16]

Ok, so I've got this this so far:

char userNumbers[5];

    cout << "\t Welcome, I will try to guess the minimum and maximum" << endl;
    cout <<  "\t           numbers of your chosen numbers." << endl;

    cout << "\nPlease 5 Enter Your Numbers here: " << endl;
        cin >> userNumbers;
    cout << "Your Chosen Numbers: " << userNumbers;

But I have a problem.
When I enter the 5 numbers. The cout << "Your Chosen Numbers: " << userNumbers; part only outputs the first numbers that is entered, how can I make it so it outputs all 5 numbers?

[Moschops]

cin >> userNumbers[5];

This will try to store the input in userNumbers[5].... which does not exist. When you create an array of size 5, like this:
char userNumbers[5];
the following array elements are created:

userNumbers[0];
userNumbers[1];
userNumbers[2];
userNumbers[3];
userNumbers[4];

I note that you made an array of type char. Each element can hold one char object. Did you mean to make an array of type int?

cout << "Your Chosen Numbers: " << userNumbers;

This only works by chance because it's a char array. When you make it an int array, you will have to output each element individually. You need to go and read about arrays.

[DJLad16]

I note that you made an array of type char. Each element can hold one char object. Did you mean to make an array of type int?

Well when I make the array of the type int I get a bunch of errors, one of which says

No match for 'operator>>' in 'std::cin >> userNumbers;'

and some othera which when I click takes me to a new tab called istream

[TheJJJunk]

Well when I make the array of the type int I get a bunch of errors, one of which says
No match for 'operator>>' in 'std::cin >> userNumbers;

This is because you are trying to input the entire array at once.

You want

for (int i=0; i < ARRAY_SIZE; ++i)
{
   cin >> userNumbers[i];
}

[DJLad16]

Well I've done this

for(int i = 0; i < userNumbers; ++i)
        {
            cin >> userNumbers[i];
        }

But then I get this error saying

ISO C++ forbids comparison between pointer and integer

Which I can't figure because I haven't even used a pointer, or have I even learnt them yet.
Btw way, with you putting ARRAY_SIZE; did you want me to put my char array userNumbers?

[cire]

Which I can't figure because I haven't even used a pointer, or have I even learnt them yet.

But you did. An array name without a subscript serves as a pointer to the first element in most contexts.

Btw way, with you putting ARRAY_SIZE; did you want me to put my char array userNumbers?

No. He wanted you to put the size of the array. (Restated: He wanted you to replace ARRAY_SIZE with the number of elements in the array.)

[DJLad16]

Thanks Cire :D I've now managed to nearly finish my program. But this code that I added to print out the chosen numbers.

for(int i = 0; i < 5; ++i)
        {
        cout << "Your Chosen Numbers: " << userNumbers[i] << endl;
        }

Prints out like
Your chosen numbers: x
Your chosen numbers: y
etc..
Is there any other code that I can write to make print out the numbers on one line? i.e Your Chosen Numbers: x, y, etc..

[maeriden]

Try to figure it out :)
What you want is to print "Your chosen numbers: " once, then cycle through the elements in the array and print each one of them (without printing a newline of course), then print a newline at the end of everything

[TheJJJunk]

Replace endl with " "