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a simple algorithm

smelas (26)
below is a part of my code but I am looking for a way to make it shorter. ?

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int box1=0;
int box2=0;
int box3=0;
int box4=0;
int box5=0;

std::cin >> number;

if ( number > 2.0 && number < 2.5 ) box1 += 1.;
if ( number > 2.5 && number < 3.0 ) box2 += 1.;
if ( number > 3.0 && number < 3.5 ) box3 += 1.;
if ( number > 3.5 && number < 4.0 ) box4 += 1.;
if ( number > 4.0 && number < 4.5 ) box5 += 1.;


thanks.
Ch1156 (1999)
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int box1=0, box2=0, box3=0, box4=0, box5=0;

std::cin >> number;

if ( number > 2.0 && number < 2.5 ) box1 += 1.;
if ( number > 2.5 && number < 3.0 ) box2 += 1.;
if ( number > 3.0 && number < 3.5 ) box3 += 1.;
if ( number > 3.5 && number < 4.0 ) box4 += 1.;
if ( number > 4.0 && number < 4.5 ) box5 += 1.;
ne555 (10692)
Take a look at arrays.
Develop an equation to obtain the box by passing the number.
maeriden (872)
This is what I managed. It was fun

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#include <cmath>
int boxes[5] = {0, 0, 0, 0 ,0};
int i;
float number;
float step = 0.5;
float lowest = 2.0;
float highest = 4.5;

std::cin >> number;

if(number > lowest && number < highest) // Checks if the input is out of range
{
    if(std::fmod(number, step) != 0) // Checks if the remainder of number/step is different from 0. This is to exclude values like 2.5, 3, 3.5, etc
    {
        i = int((number - lowest) / step);
        boxes[i] += 1;
    }
}


I must say that I didn't test the code, so I can't guarantee for it
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