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Adding a user's choice.

joshsmith01 (21)
I am giving the user a choice. He inputs the difficulty level he wants to attempt and the code acts appropriately. I don't know how to go about this. I can prompt for the choice and store it. I don't know how to implement it.

Currently, I have my code set up to randomly generate 2 numbers in between 1 and 9. That is the easyQuestions. The hardQuestions will be randomly generated numbers from 1-99. The user will have to multiply those.

I only have the first part, where there is no choice and I don't know how to implement one.

functions, how? if...else, how?

I am going to include my code.

-Josh
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#include <iostream>
#include <cstdlib>
#include <iomanip>
#include <string>
#include <ctime>
#include <cmath>
#include <fstream>
using namespace std;











int main(int argc, const char * argv[])
{  
    
    
        
    
    //upon recieving a desired level program shall take the student to funciton 1 or function 2
    
    
    
    double correctAnswer = 0;
    double incorrectAnswer = 0;
    double percentCorrect;
    int level;
    
    
    cout << "What difficulty level would you like to try?\n" ;
    cout << "Enter 1 for easy problems or 2 for harder problems.\n";
    cin >> level;

    
    
        for(int counter = 1; counter<=5; counter++)
        {
            
            
            srand( (unsigned)time(0) );//randomize the randomizer with time as the seed
            double x = rand()  % 9 +1;//randomly generated number between 1 and 10
            double y = rand() % 9 +1;//randomly generated number between 1 and 10
            
            double product = x * y;//the correct answer
            
            double answer;//student's answer input
            
            cout << "What is " << x << " times " << y << "?" << endl;//prompt user for mulitplication answer to randomly generated problem
            
            cin >> answer;//users answer to be checked and compared with computer's product
            
            
            if (answer == product)//checking to see correctness of user's answer
            {
                ++correctAnswer;
                int goodStatement = rand()  % 3 +1;
                switch (goodStatement)
                {
                    case 1:
                        puts("Very good!");
                        break;
                    case 2:
                        puts("Excellent");
                        break;
                    case 3:
                        puts("Nice work!");
                        break;
                    case 4:
                        puts("Keep up the good work");
                        break;
                        
                    default:
                        puts("Default good");
                        break;
                }

            }
            
            else
            while (answer!= product)
            {//while loop shall run with the same x and y values being presented. The program will not move forward until a correct answer is entered by user.
         
                ++incorrectAnswer;
                int badStatement = rand()  % 3 +1;
                switch (badStatement)
                {
                    case 1:
                        puts("No. Please try again");
                        break;
                    case 2:
                        puts("Wrong. Try once more");
                        break;
                    case 3:
                        puts("Don't give up");
                        break;
                    case 4:
                        puts("No. Keep trying");
                        break;
                    default:
                        puts("This is the default no");
                        break;
                }

                cout << "What is " << x << " times " << y << "?" << endl;
                cin >> answer;
            
            if (answer == product)//checking to see correctness of user's answer
            {
                ++correctAnswer;
                int goodStatement = rand()  % 3 +1;
                switch (goodStatement)
                {
                    case 1:
                        puts("Very good!");
                        break;
                    case 2:
                        puts("Excellent");
                        break;
                    case 3:
                        puts("Nice work!");
                        break;
                    case 4:
                        puts("Keep up the good work");
                        break;
                        
                    default:
                        puts("Default good");
                        break;
                }       
            }
        }            
    }
    
    cout << "You got " << correctAnswer <<" of them correct. Great work!" << endl;
    cout << "You missed " << incorrectAnswer << "." << endl;

    percentCorrect = (correctAnswer / correctAnswer + incorrectAnswer)*100;
    cout << percentCorrect << (setprecision(2)) << "%" << endl;
        if (percentCorrect < .75) {
            cout << "Please ask you teacher for extra help." << endl;       
        } else {
            cout << "Congratulations, you are ready to go the next level!" << endl;
        }     
}
Xenphibian (7)
Hint: What are you really asking?

If easy questions are random numbers from 1-9 and harder questions are 1-99... what is the real difference in your program?

Xen
joshsmith01 (21)
Hi Xen,

I am asking, if the user choses difficulty 1 how do I only run that code? If the user chooses difficulty 2 how do I only run that code?

Lines 46-48 define variables x and y with random numbers of 1-9. How can I make that a choice (difficulty 1)?

-Josh
TheJJJunk (181)
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if (choice == 1) // if user wants easy questions
{
   a = rand()  % 9 + 1;
   b = rand()  % 9 + 1;
}

else if (choice == 2) // if user wants harder questions
{
   a = rand() % 99 + 1;
   b = radn() % 99 + 1;
}


Then implement your multiplication and ask the user to answer the question.
joshsmith01 (21)
@TheJJJunk

That worked, thank you.

Your answer was so much simpler than what I was envisioning. I had an inkling towards an if...else statement, but I didn't even know how to implement that.

Thanks for the push.

-Josh
whitenite1 (1785)
Instead of putting TheJJJunks code so that it must read the if's each time through the counter loop, a better way would be to create 2 new variables.

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	int level, rand_x, rand_y; // Added 2 variables to hold the limits of random numbers x and y

	cout << "What difficulty level would you like to try?\n" ;
	do
	{
		cout << "Enter 1 for easy problems or 2 for harder problems.\n";
		cin >> level;
		if (level <1||level>2)
			cout << "Sorry. At the moment, there are only 2 levels to choose from.." << endl << endl;
                       // Above informs user that there are only the 2 levels at present
	} while (level <1 || level >2); // Only allows a 1 or 2, to be entered
	if (level == 1)
	{
		rand_x = 9;
		rand_y = 9;
	}
	else
	{
		rand_x = 99;
		rand_y = 99;
	}

 for(int counter = 1; counter<=5; counter++)
        // The rest of your is here...
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