Help!Printing a single byte!

[george86]

I wanted to see how float numbers were stored in computer's memory. So I typed the following code:

#include <stdio.h>

int main()
{
   float y = 5.0;
   int i;
   for(i=0;i<sizeof(float);i++)  
       printf ("\n%x",*((char*)&y+i));
   return 0;
}

The output was:

0
0
ffffffa0
40

I can't understand why in the third line instead of the third byte's value I got "ffffffa0".
Could someone provide me with an explanation?

[cire]

A: %x expects an int type, you're giving it a char type.
B: You're using signed representations when you want unsigned.

#include <stdio.h>

int main()
{
   float y = 5.0;
   int i;

   unsigned char* p = (unsigned char*)&y ;
   for(i=0;i<sizeof(float);i++)  
       printf ("\n%X", (unsigned)*p++);
   
   return 0;
}

[george86]

Thanks for help. Now it's working!