operator in C++

[JAI SINGH]

why we can not overload these operators..?

1-> ::
2-> .
3-> .*
4->?:

is there any reason behind this?

[Aceix]

This is because, it may cause serious problems or syntactically not correct.
The compiler evaluates these operators--they are not evaluated at runtime--and therefore cannot be replaced with your own runtime code.

Also, scope resolution and member access operators(::,->) work on names not values, and one cannot create a code that works on names because, C++ has to syntax for writing code that work on names.

Hope it HELPS!!!

[Aceix]

To quote Bjarne Stroustrup:

There is no fundamental reason to disallow overloading of ?:. I just didn't see the need to introduce the special case of overloading a ternary operator. Note that a function overloading expr1?expr2:expr3 would not be able to guarantee that only one of expr2 and expr3 was executed.

...

Operator . (dot) could in principle be overloaded using the same technique as used for ->. However, doing so can lead to questions about whether an operation is meant for the object overloading . or an object referred to by . ... This problem can be solved in several ways. At the time of standardization, it was not obvious which way would be best

[chipp]

There is no fundamental reason to disallow overloading of ?:.

you mean allow?

[Aceix]

@chipp

So he said...my resource:
http://stackoverflow.com/questions/5315908/why-cant-everything-be-overloaded-in-c

[JAI SINGH]

@Aceix thanx for reply...
I just have 2 Q to ask ?
1 Q-> scope resolution operator :: and member acces operator -> work on names not on values please elaborate this?

2 Q->diff b/t work on names and work on values?

[Aceix]

Working on names mean they work with the names of functions and members of a data structure, and not their values, while working on values mean, they deal with the values variable or constants or other data types contain. eg the assignment operator(=).