condition

[Sarah93]

Hi
I faced that problem:
if i = 1, j = 2

what the following prints?:

cout << (i >= 1 && j < 4) << endl;

I tried it and the output was 1
but why???
can any one explain why?
thanks

[Moschops]

Commonly true is represented as one, and false as zero. cout abides by this convention when dealing with outputting boolean values. The condition (i >= 1 && j < 4) evaluates to true.

[Disch]

true == 1
false == 0

(i >= 1 && j < 4) evaluates to true. If you cout true, it will print 1 because true == 1.

If you want it to print the words "true" and "false" instead, give it the boolalpha qualifier:

cout << boolalpha << true << endl;

[Sarah93]

ahaaaaaaaaa
thank you very much