problems with arithmetic problem

[ir2guru]

#include stdafx.h
#include <iostream>
using namespace std;
#include <string>

int main(){

// Declaring variable for Positive integer
int p = 0;
cout << " Enter a positive integer value " ;
// Collecting Positive Integer variable
cin >> p ;

// Declaring integer for average calculation
int z = 0;
// Specifying umbers of loop

for(int cnt = 0; cnt < p; ++cnt)
{

cout << cnt << " You entered : " ;

// Collecting value of integer for average calculation
cin >> z ;
// Adding Variable Values
int x = z;
int c = x + z;

// Computing Average Value
if (cnt == p - 1){

int r = x/p;
cout <<" Your Average is: " << c << std::endl;
}
}
}

Need help with this arithmetic problem, I got this assignment from a c++ book i bought.

Write an averaging program. The program must prompt the user to enter a positive integer that specifies
the number of values (n) the user wishes to average. The program must then ask the user to input these n
values. The program should then compute the average of the values inputted and output it to the user—
use the following average formula: average= a0............an/n

Your program’s output should look like the following:
Enter the number of values to average: 5
[0] = 1
[1] = 2
[2] = 3
[3] = 4
[4] = 5
Average = 3
Press any key to continue

[sigmablack]

#include <iostream>
using namespace std;

int main()
{
	cout<<"How many numbers would you enter?"<<endl;
	int no=0; int total=0; int avg=0;
	cin>>no;

	int *array = new int[no];//dynamically allocate size of array

	for(int i=0; i<no; i++)//input the numbers
	{
		cout<<"Enter number"<<i+1<<endl;
		cin>>array[i];
		total=total+array[i];//the total of all numbers entered
	}
	
	avg=total/no;//average=(sum of all/total number of all)

	cout<<"Average is: "<<avg<<endl;
	
	return 0;

}

[ir2guru]

thanks man that was helpful........

[sigmablack]

next time you ask a question, write the code in Source code Format (see right side)..
:)