How to convert char[][] to char** ?

[prefix1990]

I have a char 2d array :

char s[5][5];

//s[0][0] = ... s[0][1] =....

printf("%s",s[0]); //it's ok

char **foo;
*foo = &s[0][0];

printf("%s",foo[0]);

it cause segmentation fault !

[Disch]

char **foo;
*foo = &s[0][0];  // <- this is wrong.  This is where you're segfaulting 

foo is a pointer (a pointer to a char*).

on the 2nd line here you are dereferencing it... but it doesn't point to anything. So you are assigning &s[0][0] to random memory. That's why you segfault.

You probably want this:

char* foo = &s[0][0]; // or just:  char* foo = s[0];

printf("%s",foo);

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or....

If you want foo to point to s... like... char** foo = s;, that is not possible because s is not an array of pointers, it's an array of arrays.

You'd have to change foo to be a pointer to an array in that case:

char (*foo)[5] = &s;

printf("%s",foo[0]);

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but of course if you can use C++ you don't have to muck around with this crap and you can just use strings. Much simpler and safer.