Putting an integer number into a vector

[coolbran]

Hi everyone,

I have an int of several digits and i want to put that number into a vector where the all the digits are in separate elements. For example if i have

int number = 567;
vector <int> myvector;

I would like the zeroth element of myvector to contain 5, the first element to contain 6, and the second element to contain 7.

Thanks in advance.

[BlackSheep]

You'll need an algorithm to split the number into its digits. Since integer division always rounds down, something like this will do:

for(unsigned int i = 100; i > 0; i/=10)
{
     myvector.push_back(number/i);
     number -= (number/i)*i;
}

[coolbran]

Oh ok, i didn't think of that, but i tried your algorithm and it didn't work, but i get the idea.

thankyou

[BlackSheep]

int main()
{
	std::vector<int> myvector;
	int number = 519;
for(unsigned int i = 100; i > 0; i/=10)
{
     myvector.push_back(number/i);
     number -= (number/i)*i;
}
for(size_t i = 0; i < myvector.size(); ++i)
{
	std::cout<<myvector[i]<<std::endl;
}
getchar();
return 0;
}

This works for me. Just remember that if your number is longer than 3 digits i has to be initialized to something bigger.

[ssrun]

You can determine the number of digits in your number with this piece of code:

int digits = log10((float)number) + 1

That way, you don't need to initialize anything as it will just work.