Aid needed

[Aceix]

I want to know why the print function displays val1 and val2 wrongly

Code:

#include <iostream>

using namespace std;

template <class>
void print();

template <class T>
class test
{
    private:
        T val1,val2;
    public:
        test(T a,T b)
        {
            val1=a;
            val2=b;
        }
        test(){}
        T lowest();

        template <class>
        friend void print();
};


template <class T>
T test<T>::lowest()
{
    T temp=val1<val2 ? val1 : val2;
    cout<<"\n\nLowest number: "<<temp;
}

template <class T2>
void print()
{
    test<T2> temp;

    cout<<"\nval1 = "<<temp.val1;
    cout<<"\nval2 = "<<temp.val2;
}

int main()
{
    double x,y;

    cout<<"Enter a number: ";
    cin>>x;
    cout<<"Enter another number: ";
    cin>>y;
    test<double> obj1(x,y);
    print<double>();
    obj1.lowest();
    cin.ignore();
    cin.get();
}

[dean]

template <class T2>
void print()
{
    test<T2> temp; // ?

    cout<<"\nval1 = "<<temp.val1;
    cout<<"\nval2 = "<<temp.val2;
}

because temp is not related to object obj1 you have in main

regards
-dean

[o3hC5Di1]

Try passing the object to the print function:

template <class T2>
void print(test<T2> temp) //define temp as argument here
{
    cout<<"\nval1 = "<<temp.val1;
    cout<<"\nval2 = "<<temp.val2;
}

//...

int main()
{
    double x,y;

    cout<<"Enter a number: ";
    cin>>x;
    cout<<"Enter another number: ";
    cin>>y;
    test<double> obj1(x,y);
    print<double>(obj1); //pass it here
    obj1.lowest();
    cin.ignore();
    cin.get();
}

Hope that helps.

All the best,
NwN

[Aceix]

Thank you all. It's working perfectly!!!