helpp me m begiineer how pas pointer type array to function

[hu7sy]

#include<iostream>
#include<conio.h>

using namespace std;

void main()
{
int *temp;
temp=new int[10];
int get(int *temp);
void display(int *temp);



getch();
}

int get(int temp[])
{


for(int i=0;i<10;i++)
{

cin>>temp[i];
}
return *temp;

}

void display(int temp[])
{
for(int i=0;i<10;i++)
{

cout<<temp[i];
}
}

[TGuru]

Please, re-post your code with code tags, (you can find it under "Format:" ), and specify your problem.

[hu7sy]

it is not get values by cin

[TGuru]

Then what is it ?

[hu7sy]

can u tell me what is wrong with it.. i want to knw how to pass array pointer to function

[TGuru]

Pass the pointer to the function. You need to declare the function to take a pointer parameter.

[hu7sy]

how can u write a right code

[vlad from moscow]

#include<iostream>
#include<conio.h>
 
using namespace std;

void get( int *temp, int n );
void display( const int *temp, int n );
 
int main()
{
   const int N = 10;
   int *temp;

   temp = new int[N];

   get( temp, N );
   display( temp, N );

   getch();

   return ( 0 );
}
 
void get( int temp[], int n )
{
   for( int  i = 0; i < n; i++ ) cin >> temp[i];
}
 
void display( const int temp[], int n )
{
   for ( int i = 0; i < n; i++ ) cout << temp[i];
}