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Decimal to Binary using strings

ma21212 (8)
Hi, im trying to get my program to convert from decimal to binary (in the second part) but when I compile it I keep getting 0, I know I have to divide it by 2 using % and keep it in the loop but Im not sure how to do it. 

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#include <stdio.h>
#include <string.h>
#include <math.h>

int main()
{

 char string[100];
 int s;
 char a;
 char j;
 int sum = 0;
 int r;
 int q;

 printf("B = B to D\n");
 printf("D = D to B\n");
 printf("choose which one to convert to:");
 scanf("%c%c", &a, &j);

 if (a == 'B')
 {
        printf("enter binary number to convert to decimal: ");
        scanf("%s", string);

        for(s = strlen(string)-1; s >= 0; s--)
        {

                if(string[s] == '1')
                {
                sum = sum + pow(2, strlen(string) - (s +1));

                }
        }
 printf("the decimal number is: %d\n", sum);
 }

 if (a == 'D')
 {
        printf("enter decimal number to convert to binary: ");
        scanf("%s", string);

        while (r > 0)
        {
        r = q%2;
        q = q%2;
        }

 printf("the binary number is: %d\n", r);

 }

 return 0;
}
Last edited on
Zhuge (4664)
Well, your while loopsupposedly doing the conversion involves r and q, which are never set to anything. You should probably take the user's input into string and use it to populate r and q.
ma21212 (8)
well r and q are gonna be the remainder and quoteint from dividing the string by 2 but im not sure how to do that in the first place....
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