Really need help with this .. please help!

[persianmess]

#include <iostream>
#include <fstream>
#include <string>

using namespace std;

int main ()
{
ifstream inputFile;
inputFile.open ("proud_mary.txt");
ofstream outputFile;
outputFile.open ("ordered_mary.txt");
int counter=0;
int count=0;
int andC=0;
string word;
string target;
const int num=10;

if(!inputFile)
cout<<"file not found"<<endl;
else
{
while (inputFile >> word)
{
if (word=="and")
{
andC++;
word="XXX";
}
if (word >= target)
{
counter++;
cout<<word<<" ";
outputFile<< word<<" ";
}
if (counter % num== 0)
{
cout <<endl;
outputFile <<endl;
count++;
}
}
if (counter % num!=1);
{
count++;
}
}

cout<<endl;
inputFile.close();
cout <<endl;
cout << "Total number of words: "<< counter <<endl;
outputFile << "The number of words: "<< counter <<endl;
cout << "Total number of lines: " << count << endl;
outputFile << "Total number of lines: " << count << endl;
outputFile.close();


return 0;
}





Question to you all is, Comparing the two above strings, word and target .. Why would those two strings be compared? If you can tell me this in a way that makes any sense at all .. It's from opening a file with a whole bunch of words .. counting the words .. and the lines .. What would the function if (word >= target) do?

[Veltas]

word >= target means that word comes after target in dictionary order (or is the same word as target, as is larger than or equal to).

[Akshit]

first its wrong thing to do given that target has no value and for comparision you require that to be initialised.

and veltas I think word >= target first compares length of string then check for dictionary order. for = they must be identicle strings.But I am not sure.

[Veltas]

Akshit I looked it up on this website, it says dictionary order, or rather; compares the first non-equal characters matching them up in order.

[Akshit]

maybe then

[Veltas]

This would also allow you to check if the strings in fact matched.

It's kind of lexicographic, if the capitalisations for each position match and they're all letters. But a > Z according to this system so I suppose it's not quite lexicographical (unless you make sure all letters are the same case in the comparison).