creating a vector of strings

[abaz01]

hi all, im trying to write this program that creates a vector of strings where the strings are determined by a letter of the user's choosing.

#include<iostream>
#include<vector>

using namespace std;

int main()
{
    char cPhrase[]={'I',' ','l','o','v','e',' ','e','a','t','i','n','g',' ',
                    'a','l','l',' ','k','i','n','d','s',' ','o','f',' ','d','e','s','s','e','r','t','s','.','\0'};

    cout << sizeof(cPhrase)<< endl;

    vector<string>cString;

    for(int i=0; i<sizeof(cPhrase);i++){

    string s="";

    for(int j=0; j<1; j++)

    s+=cPhrase[i*1+j];

    cString.push_back(s);

    }

    for(int i=0;i<cString.size();i++)
    {
       cString[i];

       cout << cString[i];

    }




    return 0;
}

where if i choose the letter e the output should be

I love e ating all kinds of de sse rts.

i created the string from a char array but cant think of anything to implement that. plz help.

[vlad from moscow]

What does this loop do?

for(int j=0; j<1; j++)
s+=cPhrase[i*1+j];

And where are you choosing a letter?

[Athar]

What's with the ridiculous initialization of the char array?
char cPhrase[]="I love eating all kinds of desserts.";

Why do you need a vector? There is no need to store the parts before printing them.

i*1+j

That's quite a fancy way of saying i.

[abaz01]

it creates the string from the char array

[Cubbi]

getline() does that

#include <iostream>
#include <vector>
#include <sstream>
#include <string>

int main()
{
    char cPhrase[]={'I',' ','l','o','v','e',' ','e','a','t','i','n','g',' ',
                    'a','l','l',' ','k','i','n','d','s',' ','o','f',' ','d','e','s','s','e','r','t','s','.','\0'};
    std::istringstream buf(cPhrase);
    std::vector<std::string> cString;
    char delim = 'e';
    for(std::string word; getline(buf, word, delim); )
        cString.push_back(word + delim);

    for(size_t i=0; i<cString.size(); ++i)
       std::cout << '"' << cString[i] << "\" ";
}

(I've added quotation marks to the output to show your word boundaries better, note the caveat with the last word: geline drops the delimiter)

[abaz01]

thanks @Cubbi

[Cubbi]

PS: could also use regex to make it easier to deal with the last word:

#include <iostream>
#include <boost/regex.hpp> // or just <regex>

int main()
{
    char cPhrase[]={'I',' ','l','o','v','e',' ','e','a','t','i','n','g',' ',
                    'a','l','l',' ','k','i','n','d','s',' ','o','f',' ','d','e','s','s','e','r','t','s','.','\0'};
    boost::regex re("[^e]+(e|$)");
    boost::cregex_iterator beg(cPhrase, cPhrase + sizeof cPhrase, re), end;
    for(boost::cregex_iterator i = beg; i != end; ++i)
        std::cout << '"' << *i << "\" ";
}

"I love" " e" "ating all kinds of de" "sse" "rts."