Problem with long double

[Sava]

Hello ! This is my first time on the forum, I have done a quick search of this topic on google but didn't find an answer. Here is the code

long double ld = 60.0L;
double d = 60.0L;
cout << ld << " " << d << endl;
ld = 60.0;
d = 60.0;
cout << ld << " " << d << endl;
ld = 60;
d = 60;
cout << ld << " " << d << endl;
cout << 60 << endl;
cout << 60.0 << endl;
cout << 60.0L << endl;
cout << (double)60.0L << endl;

Here is the output (problem)

1.13259e-317 60
1.13259e-317 60
1.13259e-317 60
60
60
1.13259e-317
60

I ran into this when I was trying to use long double for simple calculations and output and so I am trying to find out what is wrong. I don't understand where this behaviour comes from. It appears to be a problem with cout displaying long double variables. Is it the compiler ?
I am using the Dev-C++ 5.2.0.3 package which I think uses some version of MinGW 4.6, including C++11 support.

[dtaqee88]

Yeah I just ran your code using codeblocks and the output for me was:

60  60
60  60
60  60
60
60
60
60

I don't know much about compilers but it could be dev-c. I've have heard dev-c has some issues....as does all compilers. Maybe play with the settings.

[guestgulkan]

but 1.13259e-317 is such a ridiculously small number compared to 60.00
i'm thinking that it could be your code rather than the compiler (it's like an unitialised variable)

[Sava]

Thank you for your replies! I am using Dev-C because I was looking for C++11 support and wanted to avoid Visual Studio and its .Net framework (I suspect having it installed is crashing my system).
Dev-C++ is a recent revival of the 2005 name. I couldn't set up MinGW with another IDE while Dev-C++ came packaged.

It appears that converting a long double variable or constant literal into double before displaying it with cout makes things work. Behind it, operations like adding, multiplying, etc., seem to go normally for long doubles.