Array Search cout problem

[BroncoAG]

I have the code pretty much done. The only problem I am having is that at Line 36 where I have the cout "Element not found" line with display 20 times multiple times if the number to be searched for is in more than one spot. I just want it to be displayed one time if the number cannot be found.

#include <iostream>
#include <iomanip>
using namespace std;

int main()
{
    int num_list[20];
    int y;


    cout << "Please provide 20 integer numbers" << endl;
    //Loop that obtains the numbers for the search
    for(int x = 0; x < 20; x++)
    {
        cout << "Enter number " << x << ":" << endl;
        //obtains the numbers for the average and stores
        //them in the array num_list
        cin >> num_list[x];
    }

    cout << "What number are you searching for?" << endl;
    cin >> y;


    //loop that compares all the numbers
    for(int x = 0; x < 20; x++)
    {
        //if it finds a match
        if(num_list[x] == y)
        {
            //it prints the location to the screen
            cout<<"Element found at index " << x << "." << endl;
        }
        else
        {
            cout << "Element not found." << endl;
        }

    }
}

[HiteshVaghani1]

take one

bool found = false;

in for loop.

 for(int x = 0; x < 20; x++)
{
        //if it finds a match
        if(num_list[x] == y)
        {
            //it prints the location to the screen
            cout<<"Element found at index " << x << "." << endl;
            found = true;
        }
}
if(!found)
{
          cout << "Element not found." << endl;
}

[BroncoAG]

thanks for the response. That worked. I thought I had it after I posted. I moved the cout to outside the loop and that fixed it from repeating 20 times but it still displayed everytime. Thanks again for your help.