User inputs letter, I say if it is a vowel or consonant

[sepetoner]

#include <iostream>
#include <string.h>

using namespace std;

char vowel[6]; //supposed to be a string that is all vowels

int main()
{

    cout << "Give me a letter, and I'll tell you if it is a vowel or a consonant: ";
    cin >> vowel;

    if ((vowel == 'a') || (vowel == 'e') || (vowel == 'i') || (vowel == 'o') || (vowel = 'u'))
        cout << "Vowel" << endl;
    else
        cout << "Consonant" << endl;

return 0;

}

I am trying to let the user input a letter, and my program will tell the user if it is a vowel or consonant. It is not running, and says error on the if line "ISO C++ forbids comparison between pointer and integer." I think my problem is the string (I am not too good with those yet). Any ideas why it is not working?

[Moschops]

vowel is an array of char. When you compare it to something, you are comparing the address of the first element (i.e. a pointer); you are not comparing the contents of that address (i.e. the letter). That's not what you want.

Use a string instead of an array of char. What's meant to happen if the user types in more than one letter?