without reference-pointer

[digrev]

hi everybody is it posibble to run this code without using neither pointer nor reference

#include <iostream>
using namespace std;

double &f();

double val = 100.0;

int main()
{
double x;

cout << f() << '\n';

x = f(); // assign value of val to x
cout << x << '\n';

return 0;
}

double &f()
{
return val; // return reference to val
}

[vlad from moscow]

Variable val is a global variable. So it is visible in the translation unit until it will not be hidden by a declarationn with the same name. So you could write much simpler

#include <iostream> 
using namespace std; 

double val = 100.0; 

int main() 
{ 
   double x; 

   x = val; // assign value of val to x 

   cout << x << '\n'; 

   return 0; 
} 

Or if you want to use a function then

#include <iostream> 
using namespace std; 

double val = 100.0; 

inline double f() { return ( val ); }

int main() 
{ 
   double x; 

   cout << f() << '\n'; 

   x = f(); // assign value of val to x 
   cout << x << '\n'; 

   return 0; 
} 

[zb0S216C]

Namespaces were created for exactly this reason:

namespace Global
{
    double &Value()
    double Value_;
}

inline double &Global::Value()
{
     return(Global::Value_);
}

int main()
{
    Global::Value() = /*...*/;
}

_Wazzak

[digrev]

thank you friends