need help in getline() and cin

[Grax]

i need a way to get input on string type which include spaces, and below code is what i have done.

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
  string name = "";
  cout << "Name: ";
  cin >> name;         // this line plus below line, only obtain one string // 
                       //after space
  getline(cin, name);  // only this line, no problem
  cout << name;
  
  getch();
  return 0;
}

my question is:
if before getline(), i have a cin,

my input >> "ab cd ef"
what i obtain >> " cd ef"

first "ab" will not count, why it happened like that? how do i obtain all "ab cd ef", can anyone please help...

[Athar]

Well, first you read a word (cin>>name), then replace it with the rest of that line (getline).
What did you expect?

[Grax]

em... actually this is just a part of my program..... before the getline(), i have many cin, something like this

cout << "\n Please enter below information:\n"
        << "  + IC Number: ";                 cin >> ic;
cout << "  + Name: ";                         cin >> name;
                                                  getline(cin, name);
cout << "  + Contact Numbers: ";       cin >> cNum;
cout << "  + E-mail: ";                         cin >> email; 

if i doesn't put "cin >> name;", it skip "getline()" and continue to next cin, and i can't key in data for name....

this is my problem....

[skarla]

#include <iostream>
#include <string>
using namespace std;

int main()
{
  string name;
  string name1;
  cout << "Name: ";
  getline(cin, name);
  cout << "second Name: ";

  getline(cin, name1);
  cout << name<<","<<name1;


}

i believe that i helped you!!!

[Grax]

#include <iostream>
#include <string>
using namespace std;

int main()
{
  string name;
  string age;
  cout << "Age: ";      cin >> age;
  cout << "Name: ";   getline(cin, name); //prompt this line
  cout << age <<","<<name;
}

what i need is something like this and what should i do to prompt cin for me to enter the "name"? i only need getline() for the "name"...

[ui uiho]

if i doesn't put "cin >> name;", it skip "getline()" and continue to next cin, and i can't key in data for name....

this is my problem....

you need to learn more about getline and cin.
cin ignores whitespace and will go input info until first whitespace is detected. getline will go until a deliminating character is reach, by default this character is \n
so if you are using cin and getline together you need to clear the \n after each cin statement or else the getline function will start and first hit the \n char, at which point it ends.

what you enter:

enter your letter: A \n

what is in the cin buffer after cin>>char c;

\n

using std::cin.ignore(); it will remove the first character from the cin buffer, which is the \n.
so now the cin buffer is empty.
then you are free to use a getline().

your corrected code:

#include <iostream>
#include <string>

int main()
{
  string name;
  string age;
  std::cout << "Age: ";  
    std::cin >> age;
    std::cin.ignore(); 
  cout << "Name: ";   getline(cin, name); //prompt this line
  cout << age <<","<<name;
return 0; //you did forget this. 
}

[Grax]

that's what i exactly need! thanks for the explanation! thanks for all the help ^.^