root with pow() not working

[pedrinho98765]

I'm trying to evaluate the root of a integer with pow() but it always return me '1'

int a = 0, b = 0;

cin >> a >> b;
cout << pow(a, 1/b) << endl;

can someone tell me why??

[Moschops]

Integer division gives you an integer.

What's 1/2? Zero.
http://ideone.com/DkLd6

So what's 1/b (assuming b is some integer greater than zero)? Also zero. What is anything to the power of zero? One.

If you want 1/b to not be zero, do not use an integer for b.

[pedrinho98765]

thanks, man!! It's just that I thought: since I'm passing the result of the '1/b' and not assigning the result to b, it should work!!!
But, thank you!!

[Moschops]

since I'm passing the result of the '1/b'

The result of 1/b is an integer, whether you assign it or not. The compiler does not have some secret "super-accurate" number that it keeps track of behind the scenes.