function does not take 3 arguments?

malik1986 (17)
Hi,

I've made a struct and I would like to put it in a function, but when I call the function i get the error: "function does not take 3 arguments".

This is my code:
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/*--------------------------------*/
#include <conio.h>
#include <iostream>
#include <string>



using namespace std;
struct test{string text; string text2; string text3;} data;
void TEXT(test data)
{
	cout << "This is the texts: " << data.text << data.text2 << data.tekst3 << endl;
}
int main()
{
	TEXT("test1", "test2", "test3");


	getch();
	return 0;
}
/*--------------------------*/


Best regards
Malik, DK
Jeff HS (71)
yo Malik

Well the problems is:
your TEXT function accepts a ***struct*** as argument and not 3 strings;

off topic: if conio.h is there just for getch() you are better off with cin.get() from the <iostream> header you get the same "press any key to continue..." effect.

i think what your trying to do is this:
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int main()
{
       data.text =   "test1";
       data.text2 = "test2";
       data.text3 = "test3";
TEXT(data);

cin.get();
return 0;
}


Jeff
Last edited on
malik1986 (17)
Thank you alot Jeff :) and thanks for the tip about cin.get()
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