Why does this malfunction when you enter letters?
#include <iostream>
using namespace std;
int main()
{
double a;
double b;
cout<< "Enter your number" << endl << "HERE:";
cin>>a;
cout<< "Your number is:" << a;
cin>> b;
cin.get();
return 0;
}
Just curious.
using namespace std;
int main()
{
double a;
double b;
cout<< "Enter your number" << endl << "HERE:";
cin>>a;
cout<< "Your number is:" << a;
cin>> b;
cin.get();
return 0;
}
Just curious.
Last edited on
This isn't malfunctioning, this is behaving exactly as programmed: the operation "cin>>a" fails because "letters" are not a value of type double, and the operation "cin>>b" also fails because you haven't corrected the first error.
"cin>>a" fails because "letters" are not a value of type double
What could I put that supports letters?
What could I put that supports letters?
If you are using one letter you should just use a char type:
char a;
This holds one character of either a letter or number.
it will save memory and if you want a short string use an array of characters.
char a [10]; // this holds up to ten characters.
Remember this: A numeric value, such as an integer, is stored as a binary code in the computer and for this to but printed out on the screen, cout (which is a smart object) must convert the number into a stream of single characters.
char a;
This holds one character of either a letter or number.
it will save memory and if you want a short string use an array of characters.
char a [10]; // this holds up to ten characters.
Remember this: A numeric value, such as an integer, is stored as a binary code in the computer and for this to but printed out on the screen, cout (which is a smart object) must convert the number into a stream of single characters.
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