create files with specified name

[Eldy Voon]

I want to create 100 files with the increment of file names included..

for example the file name are :

file #1
file #2
file #3 etc

I tried but fail, I stuck at how to convert the int increment variable into string.. help..

[Athar]

The simplest way (although not the best) is to use a stringstream:

template <class T> std::string to_string(const T& v)
{
    std::stringstream ss;
    ss << v;
    return ss.str();
}

[ui uiho]

i like to do this

savefile.exceptions(std::ofstream::failbit | std::ofstream::badbit);
        std::cout << "Enter a title for your webpage: ";
        getline(std::cin, filename); 
        hold = filename;
        filename = "/Users/home/Desktop/project/seven/"; 
        filename += hold; 
        filename += ".html"; 
        try{
            savefile.open(filename.c_str());
        }
        catch (std::ofstream::failure &e){
            std::cout << "An error has occured";
            return false; 
        }

this is some code from an old project i did.

[Eldy Voon]

can u guys give me full code? my college even din't teach class (shit)..

[Eldy Voon]

C#

for (int i = 0; i < 100; i++) File.Create(i.ToString() + ".txt");

C++

HELP :(

[ui uiho]

that code i gave you. that takes file name from user, sets its location, and says type of file. then opens the save file. what else could you want?