Unique array numbers

[moominboy]

Hi all! Very new to programming and I need a little bit of help with this please? Thanks in advance for any and all replies!

I'm trying to read in an array of set values, then output only those values which are unique and I am struggling!

This is already set up in main() btw...

{
			  int input[20]={1,2,3,4,5,1,2,6,7,8,5,9,10,10,11,12,12,13,14,20}, unique[20], x=0,y=0,hold=0;
			  for(x = 0; x < 20; x++) {				  
					  if(unique[x]!=input[x])
						  unique[x]<<input[x];	  
			  }
			  cout<<unique[20]<< "\n";
			  cout<<input[20];
}
		  cout<<hold;
		  cin.ignore();
		  }

Any clues would be great! Thanks!

[vlad from moscow]

I can suggest the following algorithm. You should check each element of the array input whether it is already present in the array unique. So there are two loops in your program. The external loop for traversing array input and the internal loop for traversing array unique. For example

const int N = 20;
int pos = 0;

for ( int i = 0; i < N; i++ )
{
   int j = 0;
   for (  ; j < pos && input[i] != unique[j]; j++ );
   if ( j == pos ) unique[pos++] = input[i];
}     

[Gaminic]

Alternatively, let one loop go 0->n and one loop go n->0. Exact same algorithm, but it results in slightly more readable code [in my opinion].

[moominboy]

Thanks very much guys! Worked it out in the end with your advice!