That code is something I think I will end up using alot. Thanks!
I decided to see if I could add a couple lines (6, 7) just to see if it would work and lo and behold it did!
Thanks again!
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char choice;
do{
... your program goes here
cout << "Do you want to find the value of another character? (y/n)"
<< endl;
cin >> choice;
} while(choice != 'n');