c program not working

[moot1]

I know this is a c++ forum but i couldn't find a c forum. so here's my question why is the total always 0 at the end of this program.

#include <stdio.h>
#include <conio.h>

int main()
{

    double num;
    double total = 0.0;
    int howmanynum;
    int operation;

    printf("Here ore your options for operations for when you'll need them later:\n");
    printf("1 for addition\n2 for subtraction\n3 for multiplication\n4 for division");

    printf("\n\nNow enter how many numbers are in your math problem: ");
    scanf("%d", &howmanynum);

    printf("\n\nEnter the first number: ");
    scanf("%lf", &num);
    total = total + num;

    for(int i = 1; i < howmanynum; i++){

        printf("\n\nEnter the operation: ");
        scanf("%d", &operation);

        switch(operation)
        {
            case 1:
            total = total + num;
            break;

            case 2:
            total = total - num;
            break;

            case 3:
            total = total * num;
            break;

            case 4:
            total = total / num;
            break;
        }

        printf("\n\nEnter the next number: ");
        scanf("%lf", &num);
    }
    printf("\n\nThe total is %lf", total);
    printf("\n\nPress any key to exit");

    getch();
    return 0;
}

[Moschops]

It's not.

If you enter 1,1 the total is 1. If you enter 2,1,1,2, the total is 2.

Your algorithm is broken, though. You need to rip it up and start again.

[moot1]

what do you mean its broken.