I need some hw help please

[guero2012]

I am having trouble getting my program to run. I was wondering if i could get some help fixing it. I do not know how to fix some of the errors. I am also open to a better way of writing it. What my programs function is suppose to be is to allow the person using it to plug in a number and a base and from their convert it to binary unless the remainder is greater or equal to ten then convert it to hex.

Help is greatly appreciated,

what I have so far is below.

#include <iostream>
#include <cmath>
#include <string>

using namespace std;
double read_int(string prompt);
double remainder(remainder);
	


double read_int(string prompt)
{
	bool done = false;
	double returnvalue = 0.0;
	while (done==false){
		cout<<prompt;
		cin>>returnvalue;
		if(cin.fail()==0){
			//done=true;
			if(returnvalue>=0.0){
				done=true;}
			else{
				cout<<"error.must be >=0.0"<<endl;
			}
		}
		else{
			cin.clear();
			cin.ignore(INT_MAX,'\n');
			cout<<"error cannot read input"<<endl;}
	}
	//while loop
	return returnvalue;
	}

	
/***************************************************************************************/						
int main(){

double number=read_int("Please enter a number: ");
	if (number < 0) 
		cout << "That is not a positive integer.\n";
			else {
				cout << number << " converted to binary is: ";
				binary(number);
				cout << endl;
double base=read_int("Please enter a base from 2 to 35: ");
	while (35>=base>=2)		
		}
/***************************************************************************************/
double binary(int number) {
	int remainder;

	if(number <= 1) {
		cout << number;
		return;
	}

	remainder = number%base;
	binary(number >> 1);    
	cout << remainder;
		if (remainder >= 10){
			printf("A");
				else if(remainder==11)
				else if(remainder==12)
					printf("C");
						else if(remainder==13)
							printf("D");
								else if(remainder==14)
									printf("E");
										else if(remainder==15)
											printf("F");
												}
}

[Lowest0ne]

This will compile:

#include <iostream>
#include <cmath>
#include <string>

using namespace std;

double binary(int number);

double read_int(string prompt)
{
	bool done = false;
	double returnvalue = 0.0;
	while (done==false){
		cout<<prompt;
		cin>>returnvalue;
		if(cin.fail()==0){
			//done=true;
			if(returnvalue>=0.0){
				done=true;}
			else{
				cout<<"error.must be >=0.0"<<endl;
			}
		}
		else{
			cin.clear();
			cin.ignore(INT_MAX,'\n');
			cout<<"error cannot read input"<<endl;}
	}
	//while loop
	return returnvalue;
}


/***************************************************************************************/						
int main(){

	int number;
	cout << "Please enter a number: ";
	cin >> number;
	if (number < 0) 
		cout << "That is not a positive integer.\n";
	else {
		cout << number << " converted to binary is: " << binary(number) << endl;
		double base=read_int("Please enter a base from 2 to 35: ");
		//while (35>=base>=2) // infinite loop
	}
	return 0;
}
	/***************************************************************************************/
double binary(int number) {
	int remainder;
	int base = 2;
	if(number <= 1) {
		cout << number;
		return 0;
	}

	remainder = number%base;
	binary(number >> 1);    
	cout << remainder;
	if (remainder >= 10)
		printf("A");
	else if(remainder==11); // nothing here
	else if(remainder==12)
		printf("C");
	else if(remainder==13)
		printf("D");
	else if(remainder==14)
		printf("E");
	else if(remainder==15)
		printf("F");

	return 0; // have to return something
}

Though there are a bunch of things that won't work right (or at all).

[Incis B]

First, I suspect you'll need to use BASE as a fnc arg inside BINARY()

Second, try using a SWITCH, so as it easier to read.

Third: double remainder(remainder);

(A) it's usually considered confusing to name things with the same name.
(B) it's not considered good form to declare a fnc that isn't used.

Fourth: why is double read_int(string prompt)
named read_int when it accepts a string ?

Lastly, Try to indent maybe 3 spaces to the right.

While all these suggestions actually do nothing to help fix the error(s), they
will help to isolate the error(s).