Help with searching an array

[paulthepenguin]

I have an assignment to do, where I have to write a program that reads some names from a file, then prints them in an out file and on the screen. Then I need to allow the user to enter a name, and have the program list what number the name is in the files. i.e.

name
name1
name2
name3
name1
name
name4


Enter a name: name1
name1 appears at position(s) 2, 5

Here's what I have so far:

#include <iostream>
#include <fstream>
using namespace std;

int main()
{
    int cnt = 0, index = 0;
    
    string names[50];
    ifstream inData("C:\\Names\\inData.dat");
    ofstream outData("C:\\Names\\coutData.out");
    cout << "Name Search Program \n";
    outData << "Name Search Program \n";
    
    while (!inData.eof())
    {
          getline(inData, names[cnt]);
          cnt++;
    }
    while (index < cnt)
    {
          outData << names[index] << endl;
          cout << names[index] << endl;
          index++;
    }
    string search;
    inData.close();
    outData.close();
    cout << "\nEnter a name to search for: ";
    getline(cin, search);
    
    int position[50];
    
    for(int count = 0; count < 50; count++)
    {
            if(names[count] == search);
            position[count];
    }
    
    cout << search << " appears at position(s) " << position[count];
    
    system("pause>nul");
    return(0);
}

[ui uiho]

you need two for loops, one to move the array along and one to set placement value for each found name. please no system functions by the way.

[paulthepenguin]

I don't understand what you're saying. Two nested for loops, or two seperate loops? And I'm required to use system functions for this class.

[zb0S216C]

Why not just 1 loop? It's all you need. If one loop is immediately proceeded by another that are similar, the Loop Fusion^[1] optimisation will take effect. It's when the compiler fuses two loops together to make 1. Here's some descriptive code to illustrate this:

Integer Array[10];

while( Not the end of input )
    Arrayn = /* User's input... */;

while( Not at the end of Array )
    /* Print the value at Arrayn */;

If the optimisation takes place, the result would be:

while( Not the end of input )
{
    Arrayn = /* User's input... */;
    Print( /* Print the value at Arrayn */ );
}

References:
^[1] http://en.wikipedia.org/wiki/Loop_fusion

_Wazzak

[paulthepenguin]

I still don't know how to do this :/

[Incis B]

I'll look a this in the morning, but I'll say that as you run down the file looking for a match, then once you find the first match, then you can STORE the rec_Num, i.e. "2" into an array and continue through the file looking for more hits , which you will, in this case, come across in record number # "5".

So one loop that scans the file
for FileSearch = recnum ; recnum < eof(); recnum++ )
if input_name = name_in_file{
a_rec_num[i] = recnum, i++;


so that when finished, your array "a_rec_num[]" contains the rec numbers

a_rec_num[0] = 2
a_rec_num[1] = 5

One LOOP
One file scan
One array filled with answers at the end.

[paulthepenguin]

Thank you very much, Incis.