Even or odd

[hurdle4]

How to write a program in which a number is accepted from the user and displays if the number is even or odd ?

[OxBADC0DE]

cin>>number;
if (number%2==1)
cout<<"The number you entered is an Odd number";
else
cout<<"The number you entered is an Even number";

[hurdle4]

What will happen when "number%2==1" is used?

[OxBADC0DE]

the user-input number will be divided by 2 and if the remainder(that is %) is (that is ==)1,that shows it is an odd number...else its an even number. Hey friend try to grab a textbook

[markode]

it's simple.
general notation for even numbers is (2n)
therefore, 2 can divide all even numbers completely.

LOGIC;

int n;
cout<<"\n Enter number:";
cin>>n;
if(n%2==0)
cout<<"\n the number is even";
else
cout<<"\n the number is odd";

[hurdle4]

Thanks Matri X and markode .

[Blessman11]

An easier way is to read the binary if you are looking for a super fast check.
Look into bitshifting!!