question about function call
I was taking a quiz on Cprogramming website, one question was:
What does the following code do:
int foo (int x, int y)
{
cout << x << y ;
}
int c=0;
foo( c++, c );
a. Undefined
b. 01
c. 00
The correct answer was a, but I test it on vs2010, the answer was b. I am confused now. Anyone could explain this? Thanks!
What does the following code do:
int foo (int x, int y)
{
cout << x << y ;
}
int c=0;
foo( c++, c );
a. Undefined
b. 01
c. 00
The correct answer was a, but I test it on vs2010, the answer was b. I am confused now. Anyone could explain this? Thanks!
Undefined means that it could be both b or c, depending on the compiler and whatever it cares about. If you compile the code you'll get a warning at most. It's even possible that most compilers would generate 01 here. However the standard says that it's undefined so you must never rely on the order of evaluation.
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