Recursion on Reversing Digits with pointers

[iamweak]

Hi guys,

Currently i am working on reversing the digits using recursion.

I have done up the code for recursion but i don't understand why i always get the output of 0.

Could u guys care to enlighten?

Thanks.

#include <stdio.h>
#include <stdio.h>

void reverseDigits(int n, int *result);

main(void)
{
int result;
int n;
int cont = 1;
while (cont) {
result = 0;
printf("Enter a number: ");
scanf("%d", &n);
reverseDigits(n, &result);
printf("result = %d\n", result);
printf("Continue (1 for yes, 0 for no): ");
scanf("%d", &cont);
}
return 0;
}


void reverseDigits(int n, int *result){


if(n>0){
return;
}
int reverseNum=reverseNum*10+(n%10);
n=n/10;
*result=reverseNum;
int x=*result;
reverseDigits(n,&x);
}

[Stewbond]

lines 27-29:

if (n>0) return;

Is that really your intent? You are effectively saying that for any number greater than 0, you will not process it. I expect that you have your >< signs mixed up.

[eypros]

Also I don't see where you initialize reverseNum in line 30. I think you are using garbage stuff here.

What reverseNum is supposed to be? The number you keep in every recursion like in n=123, in 1st recursion being 1 etc?

[iamweak]

even if it is switched to < , the program still doesn't run correctly. compilation has no error but when it runs it says that it has stopped working. any idea what went wrong?

[iamweak]

reverseNum is supposed to store the digit from the back for each recursion.

lets says n=1234
reverseNum will store 4 at first den 3 at second and so on and so forth.

den the value of n will be used to called reverseDigit function again and the value of reverseNum should b stored inside the pointer result.