searching space in a char

[gelatine]

i need a function where i can find the space. this is what i have. but when i compile it it shows no errors but when i enter something it shows nothing can someone tell me why

#include <iostream>
using namespace std;

int main()
{
	char inj[15];
	int p;
        cin >> inj;
	for (p=0;p<15;p++)
	{
		if(inj[p]==' ')
		{
		   cout << p << endl;
		}
	}
	system("pause");
        return 0;
}

output:

fail thing
press any key to continue...

[ciphermagi]

You're making it print only if it's a space. It wouldn't show anything in any case.

[Stewbond]

This is because the cin>> operator only gives you everything in that stream up to the first whitespace. This lets you do things like:

1 2 3 4 5 6 7 8

int main() { int a, b, c; cout << "Enter 3 numbers: "; cin >> a >> b >> c; cout << "The 3 numbers are: " << a << ", " << b << ", " << c << endl; return 0; }

Enter 3 numbers: 2 45 76 The three numbers are: 2, 45, 76 press any key to continue...

Instead of the cin>> operator, use the getline() function from istream like this:

#include <iostream>
using namespace std;

int main()
{
	char inj[15];
	int p;
        cin.getline(inj,15);
	for (p=0;p<15;p++)
	{
		if(inj[p]==' ')
		{
		   cout << p << endl;
		}
	}
	system("pause");
        return 0;
}

This will insert everything into inj.

Reference:
http://cplusplus.com/reference/iostream/istream/getline/

[Stewbond]

@ciphermagi: He's outputting the index, not the value of inj[p]. That was my original thought too until I took a second look.

[gelatine]

thanks

[ciphermagi]

I see it now. Yes, cin >> will only read up to (and not including) the first white space character.

[AARGH]

#include <iostream>
using namespace std;

int main()
{
char inj[15];
int p;
int how_many = 0;
cin.getline(inj, 15);
for (p = 0; p < 15; p++)
{
if(inj[p]==' ')
{
++ how_many;
cout << "space encountered on line # " << p + 1 << endl;
}
}
if (how_many == 0)
cout << "\nno spaces encountered.\n";
else if (how_many > 0)
cout << endl << how_many << " total spaces encountered.\n";
cout << "\npress enter to exit.";
cin.get();

return 0;
}

//will count and report how many total spaces and their locations on the screen.