Syntax error?????

[monkeybutt]

At the call of decTobin(), it keeps saying there is a syntax error(error C2059: syntax error : ']') but I just don't see it. Am I not seeing something very obvious??

#include <iostream>
using namespace std;


void decTobin(int, int);
//void BinaryAnd(int*, const int*, const int*)

int main()
{
	int num;
	int n = 0;
	int binNum[] = {0, 0, 0, 0, 0, 0, 0, 0};

	cout << "Enter an integer" << endl;
	cin >> num;
	decTobin(num, binNum[]);
	for(int n=0; n < 8; n++)
		cout << n << ' ' << binNum[n] << endl; 

	return 0;
}

void decTobin(int num, int binNum[])
{
	int n = 0;
	int remainder;

	if(num == 0)
	{
		return;
	}
	else if(num == 1)
	{
		int n = 0;
		while(n < 7)
		{
			binNum[n] = 0;
			n++;
		}
		binNum[n] = 1;
	}
	else if(num > 0)
	{
		while(num >= 1)
		{
			remainder = num%2;
			num = num/2;
			binNum[n] = remainder;
			n++;
		}
	}
	else
	{
                num = abs(num);
		while(num >= 1)
		{
			remainder = num%2;
			num = num/2;
			binNum[n] = remainder;
			n++;
		}
		n = 0;
		binNum[n] = 1;
		n++;
		while(n < 8)
		{
			if(binNum[n] = 0)
			{
				binNum[n] = 1;
                                n++;
			}
			else
			{
				binNum[n] = 0;
                                n++;
			}
		}
	}
}

[hamsterman]

The [] shouldn't be there. The name of the array is binNum. When not in a declaration, []s mark an operation. What kind of operation do you expect?

[monkeybutt]

I thought that at first but when I took away [], it said it couldn't convert from int [] to int.

[Wisely Done]

Change this :
void decTobin(int, int);
Into :
void decTobin(int, int []);
Also, change :
decTobin(num, binNum[]);
Into:
decTobin(num, binNum);

[monkeybutt]

Oh, I see. Silly mistake. Thank you.