Print even numbers up to 10 using 12 as predefined variable

[shangy]

//this program needs to print even numbers form 2 - 10
#include <iostream>
using namespace std;

int main()
{
int count;
int x = 0;
while (x!=10)//(x!=12)
//I used 10 instead of 12 and it works fine but it
//needs to use 12 instead 10
{
x = x + 2;
cout << x << "\n""\n";
count++;
cout << endl;
}
return 0;
}

[georgep]

Firstly, I don't see why you need count involved. Neither do you need to use endl, given that you're already using "\n".

What you've done wrong is have x = x + 2 before cout << x.
It means that the loop continues when x = 10, but will then add 2 and cout << x.

This should work just fine:

#include <iostream>
using namespace std;

int main(){

int x = 2; 
  
  while(x < 12){              
      cout << x << "\n""\n";
      x = x + 2;       
  }

return 0;
}

[shangy]

Thanks georgep...it work perfectly now.

[OxBADC0DE]

That code works ONLY for constant values,what IF the user were to supply the values and an odd number(value) were inputted?then you'll have to optimize your code farther

[shangy]

Okay MatriX, that sounds interesting....lets see the code for that, please

[OxBADC0DE]

Its this

//include everything that starts your source code blah blah
cin>>count_to;
for(int n=0;n<=count_to;n++)
{
if (n%2==0)
cout<<n;
}
/*you input the rest of the codes here 
tada */