x+1=y?

[gelatine]

i was looking at an example of pointers and it did a char with value x and the output is y after doing ++ to it.
here is code

// increaser
#include <iostream>
using namespace std;

void increase (void* data, int psize)
{
  if ( psize == sizeof(char) )
  { char* pchar; pchar=(char*)data; ++(*pchar); }
  else if (psize == sizeof(int) )
  { int* pint; pint=(int*)data; ++(*pint); }
}

int main ()
{
  char a = 'x';
  int b = 1602;
  increase (&a,sizeof(a));
  increase (&b,sizeof(b));
  cout << a << ", " << b << endl;
  return 0;
}

output:

y, 1603

[Texan40]

The ASCII code for 'x' is 120 (0x78). Adding one brings up 'y' 121 (0x79).

[gelatine]

ah ok but ive read in the chapter of pointers that we cant know the location of the address i point to yet

[Lynx876]

& - ampersand, Reference operator (&).

http://www.cplusplus.com/doc/tutorial/pointers/

Quote from the link:

The address that locates a variable within memory is what we call a reference to that variable. This reference to a variable can be obtained by preceding the identifier of a variable with an ampersand sign (&), known as reference operator, and which can be literally translated as "address of".

[clanmjc]

ah ok but ive read in the chapter of pointers that we cant know the location of the address i point to yet

This isn't incrementing the pointer, it is incrementing the value in memory the pointer is pointing to.

++(*pchar);
Broken down in order.

(*pchar) //dereferences the pointer. Any operator acting on this is acting on 'x' or 120

++('x') //translates to ++(120), same as a loop using counter ++i

[gelatine]

ok thank you.