How to stop cin into an array by entering 0?

[slofr66]

I'm trying to use cin to read numbers into an array up to size 100. The program will know that the user is done inputting numbers when a zero is entered. This is what I have so far:

  const int size = 100;
  int Array[size];
  for (int i=0; i<size; i++){
      cin >> Array[i];
      //THIS IS WHERE THINGS GO WRONG
      if (Array[i]=0){
         break;
      }
  //code to print array
  for (int n=0; n<size; n++){
      cout << Array[n];
  }

Thanks for any help you can give me! I'm confused at how to use an array without a predefined length. I feel like there is a simple solution to this but I cannot get it to work.

[Code2Code]

You used a single '=' not a '==' for line 6, but this is what I would do:

#include <iostream>

using namespace std;

const int SIZE = 100;

int main()
{
  int count = 0;
  int Array[SIZE];

  for (int i = 0; i < SIZE; i++)
  {
	  count += 1; //or you can do count++; or count = i;
	  cout << "Enter array for position " << i << ": ";

      cin >> Array[i];
    
      if (Array[i] == 0)
           break;
   }

  //code to print array
  for (int n = 0; n < count; n++)
  {
      cout << Array[n] << endl;
  }

  return 0;
}

I added a variable count to keep track of how many numbers are entered, otherwise when you print out 100 values from the array everything that isn't a value you entered will just be garbage data.

Hope that helps somewhat! :)

P.S. If you don't want to have a const predefined array size you should use a dynamic array using a pointer.

[slofr66]

Thanks! Worked beautifully! One more quick question, how would I go about removing the trailing zero from the array?

[Code2Code]

Do you mean re-size the array? If that's what you mean, you should think about either going the dynamic route, or you could use a vector instead, which you can have grow on the fly as you receive the numbers.