seat with array!!! HELP

[Beg2012]

heey people .. i have problem that i cant solve i hope you help me with it ...

i need to make seats like this :
A B C D
1 * * * *
2 * * * *
3 * * * *
4 * * * *
5 * * * *

i dont understand how to do it with arrays ... honestly i dont get it [arrays thing !!] its complicated thing ....

you dont need to give me the code you can explain it to me BRIEFLY what is the steps to do it ??!! seriously i am f*****d up with arrays !!!

[ciphermagi]

An array is very similar to a mathematical matrix. It's actually only one-dimensional, but it can be simulated to be two dimensional, as it appears that you're looking at it. Basically, you want a two-dimensional array, and you want to have the values populated with your seat numbers.

[Beg2012]

okay can u give me steps to do it ... what i have to do first ??
lets say
int seats[row][column]
how i fill it with "*" and number!!!

[ciphermagi]

Well, first things first is to match the variable type to what you want to put in it. If you intend to put * in it, then you can't use int. If it's only numbers, then int is acceptable. After that, just make a loop to iterate through each of the elements and put it's position into it's value.

[Beg2012]

can you give me example for that ??1

[ciphermagi]

int seats[4][5], seatNum = 1;

for(int i = 0; i < 4; ++i){
    for(int j = 0; j < 5; ++j){
        seats[i][j] = seatNum;
        ++seatNum;
    }
}

Edit: You can change the dimensions any way you want, and like I said, if you want to change the type of variable, you'll have to make some modifications, but this should populate the array.

[Stewbond]

To get an output like you have above you could do the following:

const int columns = 4, rows = 5; //Sets array boundries.  Const is required
char seats[columns ][rows ] = {'*'}; // fills array with * character.

cout << " ABCD";
for (int i = 0; i < rows; i++)
{
  cout << i; // Output row number
  for (int j = 0; j < columns; j++)    cout << seats[i][j]; // Output that star symbol
  cout << endl; // We've finished a row, start a new line.
}