organizing code

New to C++
Could someone organize this code for me as a working line.h, line.cpp, and main.cpp??
thank you

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#ifndef LINE_H
#define LINE_H

#include "Point.h"
using namespace std;

class Line
{
public:
    //constructors
    Line(); //default constructor
        //non-default constructor
        //copy constructor

    //getters and setters
        //getStart
        //getEnd
        //setStart
        //setEnd

    //other useful methods
        //getSlope
        //getMidpoint
        //print
        //distance

private:
    //private, helper methods
        //getABC

    Point start;
    Point end;
};

#endif /* LINE_H */

#include <iostream>
#include "Line.h"
using namespace std;


//constructors
Line::Line() //default constructor
{

}

    //non-default constructor
    //copy constructor

//getters and setters
    //getStart
    //getEnd
    //setStart
    //setEnd

//other useful methods
    //getSlope
    //getMidpoint
    //print
    //distance

//private, helper methods
    //getABC

#ifdef HAVE_CONFIG_H
# include <config.h>
#endif
#include "geom.h"
#include <math.h>
#include <libnr/nr-point-fns.h>


/* Intersect two lines */

/**
 * Finds the intersection of the two (infinite) lines
 * defined by the points p such that dot(n0, p) == d0 and dot(n1, p) == d1.
 *
 * If the two lines intersect, then \a result becomes their point of
 * intersection; otherwise, \a result remains unchanged.
 */
sp_intersector_kind sp_intersector_line_intersection(NR::Point const &n0, double const d0,
           NR::Point const &n1, double const d1,
           NR::Point &result) {
/* This function finds the intersection of the two lines (infinite)
 * defined by n0.X = d0 and x1.X = d1.  The algorithm is as follows:
 * To compute the intersection point use kramer's rule:
 *
 * convert lines to form
 * ax + by = c
 * dx + ey = f
 *
 * (
 *  e.g. a = (x2 - x1), b = (y2 - y1), c = (x2 - x1)*x1 + (y2 - y1)*y1
 * )
 *
 * In our case we use:
 *   a = n0.x     d = n1.x
 *   b = n0.y     e = n1.y
 *   c = d0        f = d1
 *
 * so:
 *
 * adx + bdy = cd
 * adx + aey = af
 *
 * bdy - aey = cd - af
 * (bd - ae)y = cd - af
 *
 * y = (cd - af)/(bd - ae)
 *
 * repeat for x and you get:
 *
 * x = (fb - ce)/(bd - ae)
 *
 * if the denominator (bd-ae) is 0 then the lines are parallel, if the
 * numerators are then 0 then the lines coincide. */
 double denominator = dot(rot90(n0), n1);
 double X = (n1[NR::Y] * d0  -
      n0[NR::Y] * d1);
 /* X = (-d1, d0) dot (n0[Y], n1[Y]) */
 if(denominator == 0) {
  if ( X == 0 ) {
   return coincident;
  } else {
   return parallel;
  }
 }
 double Y = (n0[NR::X] * d1  -
      n1[NR::X] * d0);
 result = NR::Point(X, Y)/denominator;
 return intersects;
}

/*
 New code which we are not yet using
*/
#ifdef HAVE_NEW_INTERSECTOR_CODE


/* ccw exists as a building block */
static int
sp_intersector_ccw(const NR::Point p0, const NR::Point p1, const NR::Point p2)
/* Determine which way a set of three points winds. */
{
 NR::Point d1 = p1 - p0;
 NR::Point d2 = p2 - p0;
/* compare slopes but avoid division operation */
 double c = dot(rot90(d1), d2);
 if(c > 0)
  return +1; // ccw - do these match def'n in header?
 if(c < 0)
  return -1; // cw

 /* Colinear [or NaN].  Decide the order. */
 if ( ( d1[0] * d2[0] < 0 )  ||
      ( d1[1] * d2[1] < 0 ) ) {
  return -1; // p2  <  p0 < p1
 } else if ( dot(d1,d1) < dot(d2,d2) ) {
  return +1; // p0 <= p1  <  p2
 } else {
  return 0; // p0 <= p2 <= p1
 }
}

/** Determine whether two line segments intersect.  This doesn't find
    the point of intersection, use the line_intersect function above,
    or the segment_intersection interface below.

    \pre neither segment is zero-length; i.e. p00 != p01 and p10 != p11.
 */
static bool
sp_intersector_segment_intersectp(NR::Point const &p00, NR::Point const &p01,
      NR::Point const &p10, NR::Point const &p11)
{
 g_return_val_if_fail(p00 != p01, false);
 g_return_val_if_fail(p10 != p11, false);

 /* true iff (    (the p1 segment straddles the p0 infinite line)
  *           and (the p0 segment straddles the p1 infinite line) ). */
 return ((sp_intersector_ccw(p00,p01, p10)
   *sp_intersector_ccw(p00, p01, p11)) <=0 )
  &&
  ((sp_intersector_ccw(p10,p11, p00)
    *sp_intersector_ccw(p10, p11, p01)) <=0 );
}


/** Determine whether \& where two line segments intersect.

    If the two segments don't intersect, then \a result remains unchanged.

    \pre neither segment is zero-length; i.e. p00 != p01 and p10 != p11.
**/
static sp_intersector_kind
sp_intersector_segment_intersect(NR::Point const &p00, NR::Point const &p01,
     NR::Point const &p10, NR::Point const &p11,
     NR::Point &result)
{
 if(sp_intersector_segment_intersectp(p00, p01, p10, p11)) {
  NR::Point n0 = (p00 - p01).ccw();
  double d0 = dot(n0,p00);

  NR::Point n1 = (p10 - p11).ccw();
  double d1 = dot(n1,p10);
  return sp_intersector_line_intersection(n0, d0, n1, d1, result);
 } else {
  return no_intersection;
 }
}

#endif /* end yet-unused HAVE_NEW_INTERSECTOR_CODE code */ 
Mmm... it rather goes against the spirit of this forum to solve homework problems for people. I'll give you a hint, though... header files usually contain the definition of a class. Meanwhile, main.cpp usually contains the main() function and oftentimes not that much more.

Does this help?

-Albatross
Okay, thanks for the tip...
So the first part is the header file.
I just cant figure out which one goes into main and which one is the line.cpp file.
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