Calling a function in an if statement

[nmf1992]

Hello,

I am writing a program to list the prime numbers from 1 to 10000. It is based on a template given in class. However, I don't think the if statement is calling on the function prime.

Here is the code:

// Problem 1 - prime.cpp

#include<iostream>
using std::cout;
using std::endl;

#include<iomanip>
using std::setw;

#include <cmath>

bool prime( int n );

int main()
{
int count = 0;
cout << "The prime numbers from 1 to 10000 are:\n";

for(int loop = 2; loop <= 10000; ++loop)

if (prime) {
++count;
cout<<setw(6)<<loop;

if(count%10==0)
cout<<"\n"; // end if

}

cout<<'\n'<<"There are "<<count<<" prime numbers.\n";

system("pause");
return 0;

} // end main

// function definition of prime

bool prime( int n )
{
for ( int i = 2; i<=10000; n++)
if (n%i==0){
return false;
}
return true;
}

Any help is appreciated.

[codekiddy]

if (prime)
you are passing function pointer not calling a function.
function prime is supposed to be passed with int argument.

[nmf1992]

Ok, thanks.