Display Array Index

[InterFiction]

I'm having a bit of trouble displaying an array index with a loop, what's going on here?

#include<iostream>
using namespace std;


int main()
{

char name[6] = {'j','e','r','e','m','y'};

for (int i; i == 5; i++)
{
    cout << name[i];
}


return 0;

}

[RKint]

You have to initialize int i. Furthermore, this second condition is wrong. You should write i <= 5.
Try: for (int i =0; i <= 5; i++)

[eypros]

You should initialize i as @RKint mentioned but == is not wrong and in some cases (some iterators) it's preferred than the relational operators.

[RKint]

It's wrong because it won't work lol

[ne555]

If the condition is true the loop will be executed. (while, not until)

[InterFiction]

how come it's

i <= 5

I thought that sense it start at 0 that would be true, so the loop wouldn't run.

[andywestken]

You've got your logic inverted.

For

for (int i =0; i <= 5; i++)
{
    cout << name[i];
}

1. i is set to 0
2. tests to see if it should execute the body: as 0 is less than or equal to 5, it continues
3. calls cout << name[0]
4. then it increments i by 1 to 1
5. and goes back to step 2; this time i is 1, so it's still less than or equal to 5, it continues
6. calls cout << name[1]
7. then it increments i by 1 to 2
8. and goes back to step 2; this time i is 2, so it's still less than or equal to 5, it continues
9. calls cout << name[2]
10. then it increments i by 1 to 3
11. and goes back to step 2; this time i is 3, so it's still less than or equal to 5, it continues
12. calls cout << name[3]
13. then it increments i by 1 to 4
14. and goes back to step 2; this time i is 4, so it's still less than or equal to 5, it continues
15. calls cout << name[4]
16. then it increments i by 1 to 5
17. and goes back to step 2; this time i is 5, so it's still less than or equal to 5, it continues
18. calls cout << name[4]
19. then it increments i by 1 to 6
20. and goes back to step 2; this time i is 6, so it's no longer less than or equal to 5, so the loop breaks!

Same as

int i =0;

while(i <= 5)
{
    cout << name[i];
    i++;
}