program doesnt prompt for input in getline()

[deathmoon]

string studentName;
    string studentGender;
    int studentCapacity;
    int n =0;

    cout << "Insert n:" << endl;
    cin >> n;

    Student* student = new Student[n];

    for(int i=0;i<n;++i)
    {
        cout << "Enter your name:" ; //ask for name
        getline(cin, studentName);
        cout << endl;

        cout << "Enter your Gender(Male or Female):"; //ask for gender
        getline(cin, studentGender);
        cout << endl;

        cout << "How many roomate(s) do you wish to have?:" << endl; //ask for capacity
        cout << "1. I want 1 roomate only (2 people in total)" << endl;
        cout << "2. I want 2 roomate (3 people in total)" << endl;
        cin >> studentCapacity;
        cout << endl;

    }

    system("cls");

    for(int i=0;i<n;++i)
    {
        student[i].Print(); //print student's information
    }

My problem is simple yet hard to trace.
I don't know what happen the program didn't prompt me to input student name and it straightly asked me for gender.
It just appears as：

Enter your name:
Enter your gender:

only the program asked me to input my gender..
I thought the name and gender has same getline syntax?

[biplav17]

add
cin.clear();
cin.ignore( numeric_limits <streamsize> ::max(), '\n' )

to the end of each CIN.
dont add after getline though

[deathmoon]

tried using cin instead of getline for studentName,
and I added up the code as you suggested, seems working but it works like a string cin.
I try to input 'Peter Jackson' but the result displayed will be Peter only...

[CosminNTG]

Try to do it with arrays. Instead of strings, use char st[length]. And then, read it with cin.getline(st, length). Length is an integer.

[deathmoon]

unable to debug getline with array, if I use cin.get(),
the program does not work, program did not prompt for any input and gave me some junk values when displaying information.

I tried to add cin.ignore() in line 13 in the code displayed, and it seems like working properly but it seems silly to put cin.ignore() inside a loop and it works quite badly if I just add it after cin my n since it only ignore once.
If I input my n is 2, my first student input is okay but for the input of second student the program, I managed to put the student name, but the program did not prompt for the gender etc etc...

[biplav17]

well. It worked for me. Getline should get the line. It clearly works for me

void populator(student array[] , int length)
{
     cout << "Enter your students  information in the format shown below for each student" << endl;
     cout << " Name" << endl;
     cout << " Grade" << endl;
     cout << " Gender" << endl;
     cout << " Studentnumber" << endl;
     cout << " Medperil" << endl;
     cout << " Address" << endl;
     cout << " Phone" << endl;
     
     
     for ( int m=0 ; m < length ; m++)
     {      
      
         getline (cin, array[m].name) ;  
         getline (cin, array[m].grade);
         getline (cin, array[m].gender);
         getline (cin, array[m].studentnumber);
         getline (cin,array[m].medperil);
         getline (cin, array[m].address);
         getline (cin, array[m].telephone);  
         
         
         cout << "Please Enter for Next student " << endl;
         cout << "" << endl;
                        
     }
         
         
}

It works for me.

cin >> length; c
in.clear();
cin.ignore( numeric_limits <streamsize> ::max(), '\n' ); 

your each cin command should look like this