Array and pointer

[time to c]

can someone explain what is happening in the memory when i declare this.

char *name[];

i saw this kind of code few times ago but i don't remember how to use it.

[binarybob350]

It is declaring an unsized array of pointers to chars.
The way is it declared is only useful when using with a parameter to a method/function

void SomeFunc( char *name[] param1 );

Below are some pointer examples that you would use in code.

// pointer to array of 4 char's, max string it can hold is 3 + NULL terminator
char *pPtrToChars = new char [4];
strcpy( pPtrToChars, "ABC" );

// array of pointers to array's of char's
// size is fixed at 2 during compile time
char *ArrayOfCharPtrs[2];
ArrayOfCharPtrs[0] = new char [4];
ArrayOfCharPtrs[1] = new char [4];
strcpy( ArrayOfCharPtrs[0], "DEF" );
strcpy( ArrayOfCharPtrs[1], "GHI" );

// pointer to array of pointers to array's of char's
// size is dynamic, set at runtime
int numArrays = 2;
char **pPtrToArrayOfCharPtrs = new char * [numArrays];
pPtrToArrayOfCharPtrs[0] = new char [4];
pPtrToArrayOfCharPtrs[1] = new char [4];
strcpy( pPtrToArrayOfCharPtrs[0], "JKL" );
strcpy( pPtrToArrayOfCharPtrs[1], "MNO" );

cout << pPtrToChars              << endl;
cout << ArrayOfCharPtrs[0]       << endl;
cout << ArrayOfCharPtrs[1]       << endl;
cout << pPtrToArrayOfCharPtrs[0] << endl;
cout << pPtrToArrayOfCharPtrs[1] << endl;

[time to c]

i am a super noob so please bare with me.
i didn't understood the line

char *pPtrToChars = new char [4];   // 0_o brain damage 

can you please explain it in very simple language.

i never used "new" keyword.

i can understand the rest of the code easily(because thats basic stuff :P).

[binarybob350]

new is c++ equivalent of malloc. Used to create dynamic memory. This line is creating an array of 4 chars.

static version would be
char ArrayOf4Chars[4];

[time to c]

Thanks for help.